Question

12 men and 15 boys can do a work in 6 days. 10 men and
24 boys can do the same work in 5 days. In how many days
can 8 men and 30 boys do the work?​

Answer 1

Answer:

you will have to find the number of man-days and boy-days required to do the job and equate it.

5(12M+ 16B) = 4(13M + 24B) since the same work is done they will be equal

60M + 80B = 52M + 96B

8M = 16B or M = 2B substitute 2B = M and you will get the total man-days required to do the job and it is

5( 12M + 8M) = 100 man-days

so,

x(7M+10B) = 100M

x(7M+5M)=100M

solving this x =25/3 days so 7 men and 10 boys will have to work for 25/3 days to complete the job.

Answer 2

5(12M+ 16B) = 4(13M + 24B) since the same work is done they will be equal

60M + 80B = 52M + 96B

8M = 16B or M = 2B substitute 2B = M and you will get the total man-days required to do the job and it is

5( 12M + 8M) = 100 man-days

so,

x(7M+10B) = 100M

x(7M+5M)=100M

solving this x =25/3 days so 7 men and 10 boys will have to work for 25/3 days to complete the job.

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