Math, asked by kanojiaaman55, 1 month ago

12 men and 15 women can finish a piece of work in 10 days and 21 women and 24 children can finish the same work in 15 days. in how many days 1 men ,3 women and 2 children together finish the same work, at their double efficiency?

Answers

Answered by HAZZARD
0

Answer:

12 men can do the job in 10 days. That means one man can do 1/(12*10) or 1/120 of the job per day.

15 women can do the job in 10 days. So one woman can do 1/(15*10) or 1/150 of the job per day.

7 men and 10 women will do 7/120 + 10/150 of the job per day. 7/120=35/600 and 10/150=40/600. So 35/600 + 40/600 or 75/600 or 1/8 of the work will be done each day.

It will take 8 days for the team to finish the job.

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Answered by kamaljot8816033922
1

Answer:

one day work of

12M+15W=1/10.....(1)

one day work of

21W+24C=1/15......(2)

Add equation (1)+(2)

12M+36W+24C=1/10+1/15=5/30=1/6

12(1M+3W+2C)=1/6

1M+3W+2C=1/72

so they will complete work in 72 days ,

But with double effeciency they will take half of the normal days taken ,

i.e, 72/2=36days

Ans:- 36Days

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