Math, asked by SaketUpadhyay3571, 1 year ago

12 men and 16 women together can complete a work in 4days. It takes 80 days for one man alone to complete the same work, then how meny days would be required for one woman alone to complete the same work?

Answers

Answered by JackelineCasarez
1

160 days would be required for a woman alone to complete the same work.

Step-by-step explanation:

Given,

No. of men = 12

No. of women = 16

Time taken to complete the work = 4 days

A.T.Q.

The work done by 12 men and 16 women in 4 days = work done by one man in 80 days

⇒ 12 men × 4 days + 16 women × 4 days = 80 man-days

⇒ 48 man days + 64 woman days = 80 man days

⇒ 64 woman days = 80 - 48 man days

⇒ 64 women days = 32 man days

 ∵ 2 woman days = 1 man day.

Thus, if one man alone completes the work in 80 days, the women will take;

80 * 2 = 160 days.

Learn more: In how many days, the work can be completed

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