Math, asked by sachinkpawar21, 10 months ago

12 men can build a wall in 15 days they worked for three days and then the contractor bring a team of 18 main to complete the work how many days will they now take to complete the remaining work?​

Answers

Answered by sanjeevk28012
0

Answer:

The time taken by 18 men to build the remaining wall is 8 days .

Step-by-step explanation:

Given as :

Let The 18 man can build the remaining wall in d days

Time taken by 12 men to build a wall = 15 days

i.e 12 men in 15 days make 1 wall

Or, 12 men in 1 day make \dfrac{1}{15} wall

∴, 12 men  in 3 days make \dfrac{1}{15} × 3 wall

i.e 12 men  in 3 days make \dfrac{1}{5} wall

Again

Contractor bring team of 18 men to complete the remaining work

Remaining work = 1 -  \dfrac{1}{5}

Or, Remaining work = \dfrac{5-1}{5}

Remaining work   = \dfrac{4}{5}

Now,

∵  \dfrac{men\times day}{work} = constant

So, \dfrac{12\times 3}{\frac{1}{5}}  = \dfrac{18\times d}{\frac{4}{5}}

Or, 4 × 12 × 3 = 18 × d

∴, d =  \dfrac{144}{18}

i.e d = 8 days

So, The time taken by 18 men to build the remaining wall = d = 8 days

Hence, The time taken by 18 men to build the remaining wall is 8 days . Answer

Similar questions