Math, asked by rahulguptaslg1505, 1 year ago

12 men can complete a work in 8 days. 16 women can complete the same work in 12 days. 8 men and 8 women started working and worked for 6 days. how many more men are to be added to complete the remaining work in 1 day?

Answers

Answered by pri2029
26
1man will complete work x/12 part in 8 days
and in one day x/96
similarly 1 women will complete x/192 part in one day
8 men and 8 women will work in 1 days
=8x/96+8x/192
=x/12+ x/24
=3x/24
=x/8
in 6 days work done will be= 6x/8
=3x/4
so work left = x-3x/4
= x/4
in one day 1 man can do x/96 part of work
so no. of men required will be= (96/x)(x/4)
=24

I hope it will help u
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