Math, asked by dishaa2701, 1 month ago

12 men can complete a work in 8 days 16 women can complete the same work in 12 days 8 men and 8 women started working and worked for 6 days How many more men are to be added to complete the remaining work in 1 day? n A) 12 nd B) 8 C 16 n D) 24

Answers

Answered by SHARIQUEHOSSAIN
0

Answer:

8

Step-by-step explanation:

8 is the answer option b

Answered by jaiswalnidhi1080
2

Answer : Option B) 12

Explanation:

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34 Remaining work = 1/4

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34 Remaining work = 1/4(8 men +8 women)'s 1 day work = 1(896+8192) =1/8

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34 Remaining work = 1/4(8 men +8 women)'s 1 day work = 1(896+8192) =1/8Remaining work =1/4 - 1/8 = 1/8

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34 Remaining work = 1/4(8 men +8 women)'s 1 day work = 1(896+8192) =1/8Remaining work =1/4 - 1/8 = 1/81/96 work is done in 1 day by 1 man

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192Work done in 6 days=6(896+8192)=6×18 =34 Remaining work = 1/4(8 men +8 women)'s 1 day work = 1(896+8192) =1/8Remaining work =1/4 - 1/8 = 1/81/96 work is done in 1 day by 1 man Therefore, 1/8 work will be done

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