Math, asked by madeshwaran123455, 1 month ago

12 men Or 15 women can do a piece of work in 21 days. find the number of days required to complete the same work by 6 men and 10 women




Answers

Answered by Anonymous
1

12 men = 21 days

1 man = 252 days

1 man in 1 day = 1/252 of the work

6 men = 6/252 = 1/42 of the work

15 women = 21 days

1 woman = 315 days

1 woman in 1 day =1/315 of the work

10 women in 1 day = 10/315 = 2/63 of the work

so 6men + 10 women in 1 day = 1/42 +2/63 = 7/126= 1/18

ANSWER 18 days

Similar questions