12 men or 15 women can do a piece of work in 21 days. Find the number of days required to complete the same work by 6en and 10 women
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Answer:
Step-by-step explanation:
If 12 men can do work in 21 days then 1 man can do the work in 21×12 days.
So 6 men can do the work in 21*12/6
= 42 days
If 15 women can do work in 21 days, then 1 woman can do it in 21×15 days.
So 10 women can do it in 21×15/10
= 63 days and 12 hours = 63/2 days.
They both together can do in
= (1/42) + (2/63)
= 7/126
= 126/7 days
= 19 days
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