12 ml of a gaseous hydrocarbon was exploded with 50 ml of oxygen the volume after explosion bus 32 mm on treatment with cable has the volume reduced to 1 ml then the formula of hydrocarbon
Answers
Silver articles become black when exposed to air
Explanation:
Chemical equation that represents combustion of a hydrocarbon is as follows.
It is given that volume of carbon dioxide and unreacted oxygen is equal to 32 ml.
As carbon dioxide gas is absorbed by potassium hydroxide. So, when 32 ml of this mixture is treated with KOH then it is reduced to 1 ml.
Hence, amount of formed is (32 ml - 1 ml) = 33 ml.
Therefore, amount of unreacted oxygen = 1 ml
Volume of reacted oxygen = 50 ml - 1 ml = 49 ml
Volume of hydrocarbon is given as 12 ml.
Therefore, applying the principle of atom conservation on C as follows.
moles of = 1
No. of moles of will be calculated as follows.
x = 2.7 = 3 (approx)
Now, applying the principle of atom conservation on H as follows.
....... (1)
Now, applying the principle of atom conservation on O as follows.
no. of moles of = 1 \times /text{no. of moles of} H_{2}O + 2 \times /text{no. of moles of} CO_{2}[/tex]
No. of moles of =
y = 6
Hence, molecular formula of the given hydrocarbon is .