Question

12. Mr Lee left his fortune to his 3 sons, 4 daughters and his wife. Each
son received twice as much as each daughter and his wife received
$6000, which was a quarter of the money. How much did each son
receive?​

Answer 1

Answer:

3600

Explanation:

Find the total amt (A) using the wife's share

.25A = 6000

Multiply both sides by 4

A = 4(6000)

A = $24,000 total

:

Children share: 24000 - 6000 = $18,000

:

"Each son received twice as much as each daughter "

let x = each son's share

then

.5x = each daughters share

:

3x + 4(.5x) = 18000

3x + 2x = 18000

5x = 18000

x = 

x = $3600 for each son

Answer 2

25A = 6000

Multiply both sides by 4

A = 4(6000)

A = $24,000 total

:

Children share: 24000 - 6000 = $18,000

:

"Each son received twice as much as each daughter "

let x = each son's share

then

.5x = each daughters share

:

3x + 4(.5x) = 18000

3x + 2x = 18000

5x = 18000

x = 

x = $3600 for each son

:

:

Confirm this by finding the total (each daughter: .5(3600) = 1800)

3(3600) + 4(1800) + 6000 =

10800 + 7200 + 6000 = 2400