Question

12 ohm resistor is connected in series with a parallel combination of 10 resistor each of 200. What is the net resistance of the circuit

Answer 1

5he net resistance is

$= 12 + \frac{200}{10} \\ = 12 + 20 \\ = 32 \: \: ohm$

Answer 2

firstly 10 ressistors are in parallel of 200 ohm

1/200+1/200+1/200 ten times=1/Rp

1/200*10=1/Rp

1/20=1/Rp

Rp=20 ohm

now it is in series with 12 ohm

net resistance=20+12

=32ohm