12. On a foggy day, drivers of 2 trains travelling in opposite a
each other when they are 80 m apart travelling at 72 km
- trains travelling in opposite direction on the same railway track spot
they are 80 m apart travelling at 72 km/hr and 60 km/hr respectively. Both apply
brakes simultaneously retarding their engines at uniform rate of om
which collision is averted.
retarding their engines at uniform rate of 5 m/s. Determine the distance by
Answers
Answer:
Step-by-step explanation:
Given:
Speed of first car = 72 Kmph = 72000 m/60*60 = 72000/3600 = 20m/s
Rate of retardation = -5
Wkt,
Initial velocity = 0
0 – 400 = -10s
S = 400/10 = 40m
It will stop after travelling 40m
Similarly for second car, speed = 60 kmph = 60000/60*60 = 16.667 m/s
Rate of retardation = -5 m/s2
Wkt,
Initial velocity = 0
0 – 277.89 = -10s
S = 27.79m
The second car will stop after travelling 27.79 m
The sum of their distances = 40+ 27.79 = 67.79m which is less than the total distance between them that is 80 m
Hence no collision will occur.
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