12. One says, “Give me a hundred, friend! I shall then become twice as rich as you." The other replies, "If you give me ten, I shall be six times as rich as you." Tell me what is the amount of their respective capital?
Answers
Answer:
Then according to the question:
x+100=2(y−100)
x+100=2y−200
x−2y=−300…(1)
And,
6(x−10)=(y+10)
6x−60=y+10
6x−y=70…(2)
Multiplying equation (2) by 2, we get:
12x−2y=140…(3)
Subtracting equation (1) from equation (3), we get:
11x=140+300
11x=440
x=40
Substitute the vale of x in equation (1), we get:
40−2y=−300
40+300=2y
2y=340
y=
2
340
=170
∴ The friends had Rs. 40 and Rs. 170 with them respectively.
Let assume that,
Amount of first person be Rs x
and
Amount of second person be Rs y
According to statement,
First person said to second person, “Give me a hundred, friend! I shall then become twice as rich as you."
Thus,
Amount of first person be Rs x + 100
and
Amount of second person be Rs y - 100
So,
According to second condition
Second person said to first person, "If you give me ten, I shall be six times as rich as you."
Thus,
Amount of first person be Rs x - 10
and
Amount of second person be Rs y + 10
So,
Now, we have two linear equations.
and
can be rewritten as
On Subtracting equation (1) from equation (2), we get
On substituting x = 40, in equation (1), we get
Therefore,
Amount of first person be Rs 40
and
Amount of second person be Rs 170