12[p(a)]²+p(a)=1 What is the value of p(a) probability sum
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Step-by-step explanation:
12p(a)² + p(a) - 1 = 0
=> 12p(a)² + 4p(a)-3p(a)-1 = 0
=> (3p(a)+1)*(4p(a)-1) = 0
=> p(a) = -1/3 , 1/4
=> probability can't be -ve
=> p(a) = 1/4
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