Question

12. p(x)=x² + x - 2 polynomial​

Answer 1

$p(x) = {x}^{2} + x - 2 \\p(0) = {0}^{2} + 0 - 2 \\ = - 2$

Answer 2

Step-by-step explanation:

x² +x-2

=x²+(2-1)x-2

=x²+2x-x-2

=x(x+2)-1(x+2)

=(x+2)(x-1)

therefore,

x+2=0

x=-2

or

x-1=0

x=1