Question

12 p4 - 6 p3 + 9 p2 ÷ 3p2

Answer 1

Step-by-step explanation:

$\frac{ {12p}^{4} - {6p}^{3} + {9p}^{2} }{ {3p}^{2} } \\ \frac{ {12p}^{4} }{ {3p}^{2} } - \frac{ {6p}^{3} }{ {3p}^{2} } + \frac{9p^{2} }{ {3p}^{2} } \\ {4p}^{2} - 2p + 3$

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