Question

12 pipes are required to fill a tank in 2 hours 40 minutes. How long will it take if only 10 pipes of the same type are used?

Answer 1

Given,

12 pipes can fill the tank in 2 hours 40 minutes

To find,

The time taken by 10 pipes to fill that tank.

Solution,

We can easily solve this mathematical problem by the following mathematical process.

First of all, we have to convert the filing time of 12 pipes into simpler units.

12 pipes can fill the tank in = 2 hours 40 minutes = 120 minutes + 40 minutes = 160 minutes

(Term of unit conversion 1 hour = 60 minutes)

12 pipes can fill the tank in = 160 minutes

1 pipe can fill the tank in = 160×12 minutes

10 pipe can fill the tank in = 160×12/10 = 192 minutes = 3 hours 12 minutes

Hence, the 10 pipes will take 3 hours 12 minutes to fill the tank.

Answer 2

SOLUTION

GIVEN

12 pipes are required to fill a tank in 2 hours 40 minutes

TO DETERMINE

The time taken by 10 pipes of the same type to fill the tank

EVALUATION

Here

2 hours 40 min = 160 min

SOLVE USING RULES OF THREE

$\sf{ \: \: Number \: of \: pipes \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Time \: (Min)}$

$\sf{ \: \: \: \: \: \: \: \: \: \: \: 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 160}$

$\sf{ \: \: \: \: \: \: \: \: \: \: \: 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ?}$

Here the Number of pipes and Time are in inverse proportion

As Number of pipes decreases required time will increase

Hence the required time

$\displaystyle \sf{ = 160 \times \frac{12}{10} \: \: \: min }$

$\displaystyle \sf{ = 16 \times 12 \: \: \: min }$

$\displaystyle \sf{ = 192\: \: \: min }$

$\displaystyle \sf{ = 3 \: \: hours \: \: 12 \: min }$

FINAL ANSWER

Hence the required time = 3 hours 12 min

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