Question

12. Prove that a cyclic parallelogram is a rectangle.​

Answer 1

Answer:

Hope it helps you.

Plz Mark it as brainliest.

Answer 2

|| ✪✪ Question ✪✪ ||

Prove that a cyclic parallelogram is a rectangle.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

✰✰ Answer ✰✰

AB = CD , BC = AD

∠A + ∠C = 180° , ∠B + ∠D = 180°

To Prove : -

∠A = ∠B = ∠C = ∠D = 90°

Proof : -

∠A + ∠C = 180° ( GIVEN ) ---------( i )

Also, ∠A + ∠D = 180° ( CO-INTERIOR ) --------( ii )

By equation ( i ) and ( ii )

$\cancel{∠A}+∠C = \cancel{∠A} + ∠D$

$∠C = ∠D$

Also, ∠C + ∠D = 180° ( CO-INTERIOR )

Above we proved that $∠C = ∠D$

Here we are taking $∠D\:AS\:∠C..$

$∠C + ∠C = 180°$

$2 ∠C = 180°$

$∠C = \cancel\dfrac{180}{2}⟹90°$

So,

∠A = ∠B = ∠C = ∠D = 90°

✺Hence Proved✺