Question

12) Prove that sin2A - 2sind when A=0​

Answer 1

Step-by-step explanation:

sin2A=2sinA

⇒2sinAcosA=2sinA

⇒2sinA(cosA−1)=0

⇒sinA=0,cosA−1=0

⇒sinA=0,cosA=1

sinA=0⇒A=0,π,2π

cosA=1⇒A=0,2π

∴A={0,π,2π}∩{0,2π}

={0,2π}

Answer 2

Answer:

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