Question

12. Rajesh purchased a piece of land for * 3,50,000 and sold it at a profit of 12%.
Find its selling price.​

Answer 1

Answer:

Cost = Rs 3, 60, 000.

cost of 1/3 of the plot = Rs 1,20,000.

loss due to its sale = 20% = Rs 24,000.

cost of the second 1/3 of the plot = Rs 1,20,000

Profit due to its sale = 25% = Rs 30,000.

Net profit to be gained on the overall sales = 10% = Rs 36, 000.

Profit to be gained from the sale of third part = Rs 36,000 - 30, 000 + 24,000

= Rs 30,000

So Sale price for the last 1/3 of the plot = Rs 1,20, 000 + Rs 30, 000

= Rs 1, 50, 000.

An alternate approach:

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

Thus, SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

Or,

SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.

So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.

SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.

Hence,

SP of the remaining field = Rs. (396000-96000-180000).

= Rs. 120000.

Hope This Helps :)

btw pls brainliest me