Question

12. Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, What are
their present ages ?​

Answer 1

Step-by-step explanation:

let, Ajay age be x

and then reena age be x+6

by given condition

x+x+6=28

2x+6=28

2x=28-6

x=22/2

x=11

hence present age of Ajay is 11 year and his sister age is 17

Answer 2

Answer:

Reena's Age=17

Reena Brother's Age (Ajay)= 11

Step-by-step explanation:

Let Ajay's age be 'x'

Reena's Age = x+6

Therefore, x+x+6 = 28

2x+6=28

2x=22

x=11

Hence, Ajay's Age= 11

Reena's Age= 11+6= 17..