12 resistor is connected in series with a 6 ohm resistor and a 9 v battery sketch the circuit diagram and calculate :
(a) the resistance of the two resistors in series
(b) the current and pd each resistor
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A) equivalent resistance = 12+6=18 ohm
B) V=R(eq) I
9=18 I
1/2A=I
I in R1=1/2 A
I in R2=1/2A
V1=R1 I=12x1/2=6 V
V2=R2 I=6x1/2=3 V
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Answer:
A) equivalent resistance = 12+6=18 ohm
B) V=R(eq) I
9=18 I
1/2A=I
I in R1=1/2 A
I in R2=1/2A
V1=R1 I=12x1/2=6 V
V2=R2 I=6x1/2=3 V
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