Math, asked by wanpeng9014, 1 month ago

12. Sehar bought two dresses at 25000 each. She the
sold one of them at a loss of 10%. At what price
should she sell the second dress to gain 20% in​

Answers

Answered by anumathsfiles
2

Answer:

30,000

Step-by-step explanation:

1st dress cost price = 25000

Loss = 10 %

loss % = ( loss / c.p ) x 100

10 = ( ( c.p - s.p ) / c.p ) x 100

10 = ( ( 25000 - s.p ) / 25000 ) x 100

10 = ( ( 25000 - s.p ) / 250

10 x 250 = 25000 - s.p

2500 = 25000 - s.p

s.p = 25000 - 2500

s.p = 22500

2nd dress cost price = 25000

profit = 20 %

profit % = ( profit / c.p ) x 100

20 = ( ( s.p - c.p ) / c.p ) ) x 100

20 = (( s.p - 25000 ) / 25000 ) x 100

20 = ( s.p - 25000 ) / 250

20 x 250 = s.p - 25000

5000 = s.p - 25000

5000 + 25000 = s.p

s.p = 30,000

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