Question

12 show that cot tita + tan tita=sectita. Cosectita​

Answer 1

Answer:

$cotθ+tanθ=secθcosecθ \\ \frac{1}{tan θ} + tanθ = \frac{1}{cosθ} \times \frac{1}{sinθ} \\ \frac{1 + {tan}^{2} θ}{tanθ} = \frac{1}{cosθsinθ} \\ \frac{ {sec}^{2} θ}{tanθ} = \frac{1}{cosθsinθ} \\ \frac{ \frac{1}{ {cos}^{2}θ } }{ \frac{sinθ}{cosθ} } = \frac{1}{cosθsinθ} \\ \frac{1}{ {cos}^{2}θ } \times \frac{cosθ}{sinθ} = \frac{1}{cosθsinθ} \\ \frac{1}{cosθ} \times \frac{1}{sinθ} = \frac{1}{cosθsinθ} \\ \frac{1}{cosθsinθ} = \frac{1}{cosθsinθ} \\ LHS=RHS \\ Hence \: proved$