Math, asked by rithwikreddych80, 8 months ago

12. Simplify
2.3 x 2.3-0.3 x 0.3
2.3 x 2.3-2x2.3 x 0.3+0.3 x 0.3​

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Answers

Answered by ibranaaztechzx
3

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\0.3}

{2.3\ 2.3-0.3\0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\0.3}We can write it as,

{2.3\2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,

\{2.3\2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\times 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2

{2.3\ 2.3-0.3\ 0.3}{2.3\times 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\frac{2.3^2-0.3^2}{2.3^2-2\times 2.3\times 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\frac{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\times 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}=1.3

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}=1.3Therefore, \{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}=1.3

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Answered by guideboy509
7

Answer:

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\0.3}

{2.3\ 2.3-0.3\0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\0.3}We can write it as,

{2.3\2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,

\{2.3\2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\times 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2

{2.3\ 2.3-0.3\ 0.3}{2.3\times 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\frac{2.3^2-0.3^2}{2.3^2-2\times 2.3\times 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\frac{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\times 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}

{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}=1.3

\{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}We can write it as,=\{2.3^2-0.3^2}{2.3^2-2\ 2.3\ 0.3+0.3^2}Applying property,a^2-b^2=(a+b)(a-b)a^2-2ab+b^2=(a-b)^2=\{(2.3-0.3)(2.3+0.3)}{(2.3-0.3)^2}=\{(2)(2.6)}{(2)^2}=\{5.2}{4}=1.3Therefore, \{2.3\ 2.3-0.3\ 0.3}{2.3\ 2.3-2\ 2.3\ 0.3+0.3\ 0.3}=1.3

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