Question

12. Simplify
(x2-3x-40)
(x²+2x-15)​

Answer 1

1. $\huge\tt\red{Q}\tt\pink{U}\tt\blue{E}\tt\green{S}\tt\purple{T}\tt\orange{I}\tt\orange{O}\huge\tt\red{N}$

$\huge\tt\colorbox{pink}{Answer}$

(x-8) (x+5)

1.$\huge\tt\colorbox{aqua}{Step by step}$

$\huge\tt\colorbox{yellow}{Solution}$

Use the sum product pattern

x² + 3x -40

x² + 5x - 8x - 4

Common factor from the two pairs

x² + 5x - 8x -40

x(x + 5) - 8(x + 5)

Rewrite in the factored form

x(x-5)-8(x+5)

(x-8) (x+5)

:• (x-8) (x+5)

2.$\huge\tt\red{Q}\tt\pink{U}\tt\blue{E}\tt\green{S}\tt\purple{T}\tt\orange{I}\tt\orange{O}\huge\tt\red{N}$

(x²+2x-15)

$\huge\tt\colorbox{pink}{Answer}$

(x−3)(x+5)

2. $\huge\tt\colorbox{aqua}{Step by step}$

$\huge\tt\colorbox{yellow}{Solution}$

To Factorise : x² +2x−15

By splitting the middle term

=x² +5x−3x−15

=x(x+5)−3(x+5)

=(x−3)(x+5)

So, x² +2x−15

=(x−3)(x+5)

Hope it helps u

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