Question

12
somehow, an ant is stuck to the rimorat
bicycle wheel of diameter Im. while the
bicicle is on a central Stand, the wheel
frequency into rotatione and it allains thet
frequency of a revisec in to sec, with unft
accleration calculate
1. No. of
these
revolution
to second.
completed
by the
ant in these 10 sec
å​

Answer 1

Answer:

Given :

Diameter of bicycle wheel = 1 m

The frequency attained by the wheel in 10 s =

To Find :

i) No of rev completed by ant in 10 sec = ?

ii) Time taken for 1st complete revolution and also for last complete revolution = ?

Solution :

We know that 1 rev =2π rad

Initially the bicycle is on central  stand so initially :

And also

Now we can find the uniform angular acceleration α by  the equation  :

Or,

Or,

Now the angle covered in these 10 sec can be found as :

 

 = rad

So, no of revolutions =  = 10 rev

Now , for the complete  first revolution it would cover 2π rad , so time taken will be given by using equation :

Or,

So, t = 3. 16 sec

Now to find the time it take to complete last complete revolutions , we can find the time taken for 1st 9 rev and subtract it from the total time taken , i.e.  from the time taken to complete 10 rev which is 10 sec .

  -  (1)

So, the time taken  for 1st 9 rev is :

Or,

Or, t = 9.48 sec

So from eq 1 we get the time for last rev as :

sec

               =0.52 sec

So, the total no  of revolutions in 10 sec is 10 , time taken to complete 1st rev is 3.16 sec and  time to complete last rev is 0.52 sec .

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