Question

12. State the following expressions when x=2, y = 3, z =(-4).
(i) x²y + y²z
(ii) –3x2 – 4y2 + 6z?​

Answer 1

Answer:

(i) x²y+y²z.

x=2, y=3 & z=(-4).

(2)²(3)+(3)²(-4).

(4)(3)+(9)(-4).

12-36. (Because +×-=-).

-24. (Because +×-=- & largest number is important).

(ii) -3x²-4y²+6z.

x=2, y=3 & z=(-4).

-3(2)²-4(3)²+6(-4).

-3(4)-4(9)-24. (Because +×-=-).

-12-36-24.

-48-24. (Because -×-=+ & largest number is important).

-72. (Because -×-=+ & largest number is important).

I think this is your answer.