Question

12. Subtract a - 2b - c from the sum of 3a - b + c and
a + b - 3c.​

Answer 1

Answer:

3a+2b-c

Step-by-step explanation:

[(3a-b+c)+(a+b-3c)]-(a-2b-c)

=(3a-b+c+a+b-3c) -(a-2b-c)

=4a-2c-a+2b+c

=3a+2b-c

Answer 2

Answer:

$(3a - b + c) - (a - 2 b - c)\\ = 3a - b + c - a + 2b - c\\ = (2a + b)$