12 subtracted from 7 times a number is equal to the square of the number
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let, number is x
12 substrated 7 times a number = 7x-12
square of number= x²
then equation ,
x²= 7x-12
x²-7x+12=0
x²-x(4+3)+12=0
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-3)(x-4)=0
(x-4)= 0 or (x-3)=0
x=3 or 4
number is 4 or 3
..
12 substrated 7 times a number = 7x-12
square of number= x²
then equation ,
x²= 7x-12
x²-7x+12=0
x²-x(4+3)+12=0
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-3)(x-4)=0
(x-4)= 0 or (x-3)=0
x=3 or 4
number is 4 or 3
..
Answered by
0
Let the no. be x
According to question(ATQ)
7x-12=x^2
x^2-7x+12=0
x^2-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-3) or (x-4)=0
x=3 or x=4
I hope it will help u buddy.
Pls mark it as brainliest ans brother.
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