Question

12. Suitable quadratic equation for the situation
"The product of two consecutive integers is 600".
A) x2 + x + 600 = 0
B) x2 + x - 600 = 0
C)x2-x + 600 = 0
D) x2 - X - 600 = 0​

Answer 1

let the 2 consecutive integers be x and x+1

therefore, by condition,

(x)(x+1)=600

x^2+x=600

x^2+x-600=0

therefore b) is correct option..

please mark me down as a BRAINLIEST...!!!

Answer 2

Answer:

$\huge\boxed{\fcolorbox{red}{orange}{Solution:}}$

$Let\ the\ two\ no.\ be\ x\ and\ x+1\\</p><p>A/Q\\</p><p>(x)(x+1)=600\\</p><p>=>{x}^{2} +x=600\\</p><p>=>{x}^{2} +x-600=0$

Hence,option b is correct..