Question

12. The A.M between two numbers is 20 and G.M is 16. Find the numbers.​

Answer 1

Step-by-step explanation:

Am = 20 ,

G.M = 16

so , Am = a+b /2

20 = a+b /2

40 = a+ b eq...1

Now , G.M =

$\sqrt{ab}$

16 = root ab

root 16 = ab

4 = ab eq...2

Now from eq...2

we get , a =4/b , put in eq 1

we get , 4/b+ b = 40

$4 + {b}^{2} \div b \: = 40$

b square -40b + 4= 0

on solving we get the value of b

and put value of b in eq ...1

we get value of a .... solve