Question

12. The angles of elevation of the top of a vertical tower from two points 3
metres apart, and on the same straight line passing through the base of
tower, are 30 and 60° respectively. The height of the tower is:
O
10 m
O 15 m
15 73 m
O 30 m​

Answer 1

Answer:

10th

Maths

Some Applications of Trigonometry

Heights and Distances

The angles of elevation of ...

MATHS

The angles of elevation of the top of a vertical tower from two points . 30 meters apart, and on the same straight line passing through the base of tower , are 30

∘

and 60

∘

respectively. The height of the tower is

MEDIUM

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ANSWER

Let AB is tower, the angles of elevation of the top of a vertical boobs tower AB from two points D and C are 30

∘

and 60

∘

respectively.

CD= 30 metre

Let the height of tower be h metres

and BC=x m

In triangle ABC,

BC

AB

=tan60

∘

∴

x

h

=

3

.....(i)

In triangle ABD ,

BD

AB

=tan30

∘

∴

(x+30)

h

=

3

1

or

3h

=x+30

put value of x from equation (i) in equation (ii)

we get

3h

=

3

h

+30

or

3h

−

3

h

=30

or

3

2h

=30

∴h=

2

30

3

=15

3

meteres

So, height of the tower is 15

3

metre.

Answer 2

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