Question

12) The
cut
of
line passing through (3,0) and (7,6)
the axes at A, B then length
AB =​

Answer 1

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GIVEN,

A(3,0) and B(7,6)

AB=√(x2-x1)+(y2-y1)

AB=√(7-3)+(6-0)

AB=√4+6

AB=√10

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Answer 2

Answer:

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