Question

12. The diameter of the circle is 20 cm and the length of one of its chord is 12 cm. Find the
distance of the chord from the centre.​

Answer 1

Step-by-step explanation:

Diamete is 20 cm therefore radius will be 10 cm.

Hence, OA = OB = 10cm.

Draw a perpendicular OD on AB. This OD is the distance of the chord from the centre which we are required to find.

By the property of circles, we know this perpendicular OD will bisect the chord AB. Therefore, AD = DB = 6 cm.

Now, triangle ODB is a right triangle right angled at D where DB = 6cm and OB = 10cm.

Apply pythagorus theorem,

OB^2 = DB^2 + OD^2

(10)^2 = (6)^2 + OD^2

OD^2 = 64

Hence OD = 8cm

Answer 2

Answer:

8

Step-by-step explanation: