Physics, asked by manickammurugan733, 3 months ago


12. The displacement of a particle moving along X-axis with respect to time is given by x= at+bt^2-сt^3. The
dimensions of b are
b) L^0T^-3
a) L^0T^3
c) LT^-2
d) LT^-3​

Answers

Answered by Sreejith12345
1

Answer:

[x]= [bt^2]

L= bT^2

=> [b]= LT^-2

Therefore option (c) is the answer.

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