Math, asked by bhujelanusha94, 2 months ago

12. The distance between the point (1,2) and the line 3x+4y-7=0
is
a)
4
b)s
c)4/5
d)-4/5

Answers

Answered by mohan1709

0

Answer:

formula is:

|ax1+by1+c|/sqrt(a^2+b^2)

(3x1+4x2-7)/sqrt(25)

4/5

Step-by-step explanation:

4/5

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