Question

12) The first and 60th term of an AP are 7 and 125, respectively.
Find 30th term.​

Answer 1

Answer:

65 is the correct answer

Step-by-step explanation:

$a_n = a + (n-1)d$

here  a  = first term             d == common difference        n == is the no. of term

here a = 7

$a_{60} = a + 59d\\\\a_{60} = 7 + 59d\\125 - 7 = 59d$

d = 2

$a_{30} = 7 + 29d \\             = 7 + 58$

               = 65

Hope it helps!!!

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