Question

12. The molarity of 6% (W/V) solution of CH3COOH is​

Answer 1

Answer:

Moles of acetic acid =

60

10

=

6

1

∴ Molarity =

800

1/6

×1000

=

24

5

M

=0.2083M

Answer 2

Explanation:

Moles of acetic acid =6010=61

∴ Molarity =8001/6×1000

                 =245 M 

                 =0.2083M

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