Question

(12) The O, gas is collected over water at 400 K temperature in 2 L vessel. If the pressure of dry 0, gas is 32.20 bar then Find the vapour pressure of water under the same conditions ? (R = 8.314 x 10-2 L bar mol-1 K-1) (Ans. : 1.056 bar)​

Answer 1

Answer:

For O

2

​

gas collected over water, the pressure P=

V

nRT

​

P=

2 L

2 mol×0.08206 L⋅atm/mol⋅K×400 K

​

P=32.824 atm

Convert unit from atm to bar

P=32.824 atm×

1 atm

1.01325 bar

​

P=33.26 bar

The pressure of dry O

2

​

gas is 32.20 bar.

The vapour pressure of water =33.26 bar−32.20 bar=1.06 bar

Explanation: