Question

12. The perimeter of a triangle is 50 cm. One side of the triangle is 4 cm
longer than the smallest side and the third side is 6 cm less than twice
the smallest side. Find the area of the triangle.​

Answer 1

Answer:

Let the smallest side of the triangle be x cm long

So, second side =(x+4)cm

and third side =(2x−6)cm

Given, perimeter =50cm

Therefore, x+(x+4)+(2x−6)=50

⇒4x=52

⇒x=13cm

So, first side of the triangle is 13cm, second side be 17cm and third side is 20cm.

Now, semi-perimeter of the triangle =

2

13+17+20

=25cm

Therefore, area of Δ=

s(s−a)(s−b)(s−c)

=

25(25−13)(25−17)(25−20)

=

25×12×8×5

= 20

30

cm

2

Answer 2

Answer:

Step-by-step explanation:

let smallest sides by x

x+x+4+2x-6=50

4x=52

x=13

the sides are 13,17,20

AREA=√S(S-A)(S-B)(S-C)

=√25(12)(8)(5)

=109.544