Question

12. The product of three integers is – 600. If two of
them are -15 and 10, the third integer is
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Answer 1

Answer:

-595

Step-by-step explanation:

let the third integer be=X

product of three integers =-600

two of them =-15+10=-5

X+(-15+10)=-600

X+(-15)=-600-10

=-610

X=-610+15

=-595

Answer 2

Answer:

The answer is = (-4)

Step-by-step explanation:

To find the third integer

The product[i.e. result after multiplication] of three[3] integers is - 600

If two[2] of them are (-15) and 10

Step = Let the third integer be 'x'

First integer = (-15)[Given]

Second integer = 10

Product of three(3) integers = 600[Given]

According to the question{ATQ]

Product[result after multiplication = product] of three(3) integers is 600, so

That is,

(-15) X 10 X x[Third integer] = 600

-150([-15] X 10) X x = 600

-150x[ -150 X x[Third integer]) = 600

Follow the rules of linear equation

x = $\frac{600}{-150}$

As we know that denominator of any fraction cannot be negative

So,

x = $\frac{-600}{150}$

  = $\frac{-60}{15}$

x = -4[Third integer]