Math, asked by santoshthalla143, 1 month ago

12. The quadratic equations
having 1/a,1/ß ​

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Answered by MysticSohamS
1

Answer:

hey here is your answer

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Step-by-step explanation:

so \: here \: for \: a \: certain \: quadratic \: equation \\ its \: roots \: are \: 1/ \alpha  \: and \: 1/ \beta

so \: we \: know \: that \\ general \: formula \: of \: quadratic \: equation \: (in \: terms \: of \:  \alpha  \: and \:  \beta ) \: is \: given \: by \\ x {}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta  = 0 \\ wherein \:  \alpha  \: and \:  \beta  \: are \: its \: two \: roots

so \: hence \\ x {}^{2}  -( 1/ \alpha  + 1/ \beta )x + 1/ \alpha  \times 1/ \beta  = 0 \\ x {}^{2}   -  ( \alpha  +  \beta / \alpha  \beta )x + 1/ \alpha  \beta  = 0 \\ x {}^{2}  - ( \alpha  +  \beta )x + 1/ \alpha  \beta  = 0 \\ dividing \: and \: multiplying \: throughout \: by \:  \alpha  \beta  \\ we \: get \\  \\  \alpha  \beta .x {}^{2}  - ( \alpha  +  \beta ) + 1 = 0

hence \: the \: quadratic \: equation \: whose \: roots \: are \: 1/ \alpha  \: and \: 1/ \beta  \: is \\  \alpha  \beta .x {}^{2}  - ( \alpha  +  \beta )x + 1 = 0 \\ ie \: option  \: \: (D) \: is \: ryt

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