Chemistry, asked by vikramsh1975, 3 days ago

12 The rate law for a reaction between the substances A and B is given by Rate = k [A]" [B]M On doubling the concentration of A and halving the concentration of B, theſratio of the new rate to the earlier rate of the reaction will be as (a) (m + n) (b) (n - m) 1 (c) 2(n-m) (d) 3(m + n)​

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Answered by sanjivthakurj7
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