12. The ratio of the present ages of two brothers is 1 : 2 and 5 years back, the ratio was 1 : 3. What will be the ratio of their ages after 5 years? [SSC) (a) 1:1 (b) 2:3 (c) 3:5 (d) 5 6 will be twice the age of his son.
Answers
Answered by
94
❍ Let's Consider that, the ages of the two brothers are x years and 2x years respectively.
— Five years back :
- First brother's age = (x – 5)
- Second brother's age = (2x – 5)
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- It is given that five years back, the ratio of their ages was 1 : 3. Therefore,
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Hence,
- First brother's age = x = 10 years
- Second brother's age = 2x = 2(10) = 20 years
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★ Ratio of their ages after five years :
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Answered by
314
- Option c)
- 3:5 is correct Option ✓
Given : The ratio of present ages of two brothers is 1 : 2 and 5 years back, the ratio was 1 : 3.
To Find : Find the ratio of their ages after 5 years ?
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Solution : let's say that the present ages of the two brothers be x & 2x.
- Five years back, the ratio of their ages (both brother's ages) was 1 : 3.
Therefore,
- Five years ago their ages —
◗Younger brother = (x – 5)
◗Elder brother = (2x – 5)
★
Henceforth,
- Present ages of both brother are, x = 10 years
- 2x = 2(10) = 20 years
◗Present ages of two brothers are 10 years & 20 years.
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R A T I O :
- After five years the ratio their ages will be –
★
Hence,
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