Question

12. The sides of a rectangular park are in the ratio of 3 : 2 and its area is 3750 m². Find the cost of
fencing the park at the rate of 50 paisa per metre.​

Answer 1

Answer:

• 12500 paisa or 125 rupees is the cost.

Step-by-step explanation:

Given

• Sides of a rectangular park are in the ratio of 3 : 2
• Area = 3750 m²
• Cost of fencing the park = 50 paisa / m

To find

• Cost of fencing the park

Solution

Sides are nothing but length and breadth:

• Length : Breadth = 3 : 2

(3x) × (2x) = 3750

• 6x² = 3750
• x² = 625
• x = √625
• x = 25

Hence, the sides are:

• 3x = 3(25)
• 3x = 75 m
• 2x = 2(25)
• 2x = 50 m

Now, fencing the park means the perimeter.

Perimeter = 2(l + b)

• 2(75 + 50)
• 2(125)
• 250 m

Now:

• 1 m = 50 p
• 250 m  = ?
• 250 m = 250 × 50
• 250 m = 12500 p

Hence, the cost of fencing the park is 12500 paisa.

or 12500 × 1 rupee / 1 paisa = 125 rupees.

1 rupee = 100 paisa