12. The simple interest on a certain sum for 2 years at 12% per annum is 2100. Find the corresponding compound interest.
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Answer:
3x3y2×(2x−3y)
=3x3y2⋅2x−3x3y2⋅3y
=6x4y2−9x3y3
Now, for x=−1,y=2, we have
L.H.S.-
3x3y2×(2x−3y)
=3(−1)3(2)2(2⋅(−1)−3⋅(2))
=3⋅(−1)⋅4×(−2−6)
=(−12)×(−8)
=96
R.H.S.-
6x4y2−9x3y3
=6(−1)4(2)2−9(−1)3(2)3
=6⋅1⋅4−9⋅(−1)⋅8
=24+72
=96
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