Question

12. The slope-point equation of a line passing through the points (-3, -1) and (2, -6) is:
A.y-1 = -(x-3)
B.y+1 = -(x-3)
C.y-1 = x-3
D.y+1 = x+3

Answer 1

Step-by-step explanation:

use slope form y-y/x-x

2-(-3)/-6+1

5/-5

m=-1

y-y=m(x-x

y+1=-1(x+3)

is the answer of this question

Answer 2

Given : the points (-3, -1) and (2, -6)

To find : The slope-point equation of a line  passing through given points

Solution:

Slope point equation of line

y - y₁   = m (x - x₁)

(x ₁ , y₁) is point on line   & m = slope of lime

Points given are

(-3, -1) and (2, -6)

Slope m  =  (-6 - (-1)) / ( 2 - (-3))  =  -5 /5  = -1

Slope  = - 1

Using point  (-3, -1)

x ₁ = - 3  y₁ = - 1

y - (-1) = -1 (x - (-3))

=> y + 1 = -(x + 3)

option D y+1 = x+3   will satisfy (-3, -1)   but not (2, -6)

None of the given option is correct

The slope-point equation of a line passing through the points (-3, -1) and (2, -6) is:

y + 1 = -(x + 3)

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