Question

12. The sum of the digits of a two digit number is 5
If the digits are reversed, the number is reduced
by 27. Find the number.​

Answer 1

Answer:

$let \: the \: tens \: place \: digit \:be \: x \: \\ and \\ \: ones \: place \: digit \: be \: y \\ \: \: \: the \: no. = 10x + y \\ when \: the \: digits \: are \: reversed \\ \: \: \: the \: new \: no. = 10y + x \\ 10x + y - (10y + x) = 27 \\ 9x - 9y = 27 \\ x - y = 3 \\ x + y = 5(given \: condition) \\ adding \: both \: the \: equation \: we \: get \\ \: \: 2x = 8 \\ = > x = 4 \\ \: \: putting \: value \: of \: x \: in \: any \: of \\ \: the \: above \: equqtion \: we \: get \: \\ 4 - y = 3 \\ = > y = 1 \\ the \: original \: no. = 10x + y \\ = > 10 \times 4 + 1 \\ = > 41$

Step-by-step explanation:

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