12. The temperature of 600 g of cold water rises by
15°C when 300 g of hot water at 50°C is added to
it. What was the initial temperature of the cold
water ?
Answers
Answered by
1
Answer:
let the final temperature be T
Heat absorbed by water=Heat given by water
Q=mcΔT
⇒600×4.2×15=300×4.2×(50−T)
⇒T=20 °c
So initial temperature of cold body =20−15
=5 °c
Answered by
2
Answer:
5°C is the answer
Explanation:
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